Questions
Two identical straight wires are stretched so as to produce 6 beats per second when vibrating simultaneously. On changing the tension in one of them, the beat frequency remains unchanged. Denoting by T1, T2 , the higher and the lower initial tensions in the strings, then it could be said that while making the above change in tension
detailed solution
Correct option is B
Using n=12lTm; As T1>T2⇒n1>n2 giving n1−n2=6The beat frequency of 6 will remain fixed when (i) n1 remains same but n2 is increased to a new value (n2'−n2=12) by increasing tension T2.(ii) n2 remains same but n1 is decreased to a new value (n1-n1'=12) by decreasing tension T1.Talk to our academic expert!
Similar Questions
A metal wire of diameter 1.5 mm is held on two knife edges separated by a distance 50 cm the tension in the wire is 100 N the wire vibrating with its fundamental frequency and vibrating tuning fork together produces 5 beats per second. The tension in the wire is then reduced to 81 N, when the two are excited, beats are heard at the same rate. Calculate frequency of the fork.
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