Two identical straight wires are stretched so as to produce 6 beats per second when vibrating simultaneously. On changing the tension in one of them, the beat frequency remains unchanged. Denoting by T1, T2 , the higher and the lower initial tensions in the strings, then it could be said that while making the above change in tension
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a
T2 was decreased
b
T2 was increased
c
T1 was increased
d
T1 was kept constant
answer is B.
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Detailed Solution
Using n=12lTm; As T1>T2⇒n1>n2 giving n1−n2=6The beat frequency of 6 will remain fixed when (i) n1 remains same but n2 is increased to a new value (n2'−n2=12) by increasing tension T2.(ii) n2 remains same but n1 is decreased to a new value (n1-n1'=12) by decreasing tension T1.