Questions
Two identical stringed instruments have frequency 100 Hz. If tension in one of them is increased by 4% and they are sounded together then the number of beats in one second is
detailed solution
Correct option is D
Frequency of vibration in tight string n=p2lTm⇒n∝T⇒Δnn=ΔT2T=12×(4%)=2%⇒Number of beats = Δn=2100×n=2100×100=2Talk to our academic expert!
Similar Questions
A metal wire of diameter 1.5 mm is held on two knife edges separated by a distance 50 cm the tension in the wire is 100 N the wire vibrating with its fundamental frequency and vibrating tuning fork together produces 5 beats per second. The tension in the wire is then reduced to 81 N, when the two are excited, beats are heard at the same rate. Calculate frequency of the fork.
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