Two identical thin isosceles prisms of refracting angle ‘A’ and refractive index μ are placed with their bases touching each other. Two parallel rays of light are incident on this system as shown. The distance of the point where the rays converge from the prism is:
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a
hμA
b
hA
c
hμ−1A
d
μhμ−1A
answer is C.
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Detailed Solution
Given Angle of prism = ARefractive index= μMinimum deviation δ1=μ−1Aδ2=(μ−1)Atanδ1=hbb=htanδ1=htan((μ−1)A) As prism is thin. So tan((μ−1)A)=(μ−1)A∴b=hμ−1A(from the prism)