Question

Two identical thin rings A and B each of radius R are co-axially placed at a distance R. If mass of rings are m₁, m₂ respectively, then the work done in moving a mass m from centre of one ring to that of the other is [UP CPMT 2012J

Moderate

Solution

V_B = Potential at B due to A + Potential at A due to B
$V_{B} = \frac{- G m_{2}}{R} - (\frac{- G m_{1}}{\sqrt{2} R})$
$\Rightarrow V_{A} = \frac{- G m_{1}}{R} - (\frac{- G m_{2}}{\sqrt{2 R}})$
$W_{A \to B} = m (V_{B} - V_{A}) = \frac{G m (m_{1} - m_{2})}{\sqrt{2} R} (\sqrt{2} - 1)$

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