Two identical thin rings each of radius ‘R’ are co-axially placed at a distance ‘R’. If the rings have a uniform mass distribution and each has mass m1 and m2 respectively, then the work done in moving a mass ‘m’ from the centre of one ring to that of the other is:
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a
Zero
b
Gmm1−m2(2−1)2R
c
Gm2m1+m2R
d
Gm1m(2+1)m2R
answer is B.
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Detailed Solution
V1=−Gm1R−Gm22R and V2=−Gm2R−Gm12RΔV=V2−V1=−Gm2R−Gm12R+−Gm1R−Gm22R=Gm1−m21R−12RHence W=m(ΔV)=mGm1−m2(2−1)2R
Two identical thin rings each of radius ‘R’ are co-axially placed at a distance ‘R’. If the rings have a uniform mass distribution and each has mass m1 and m2 respectively, then the work done in moving a mass ‘m’ from the centre of one ring to that of the other is: