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Two identical vessels each of volume V contain identical samples of ideal gas. The pressure and temperature in each are P and 2T respectively. Now they are joined by a very narrow pipe and one of them is cooled to a temperature T and the other one is heated to a temperature 3T. The common pressure of the system now is 

a
4P/3
b
3P/2
c
3P/4
d
3P/5

detailed solution

Correct option is C

The total number of moles is same. Apply PV = nTR. 2PV2TR=P'VTR+P'V3TR. Solve for the common pressure P'

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