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Q.

Two identical wires are stretched by the same tension of 100 N, and each emits a note of frequency 200 cycles/sec. The tension in one wire is increased by 1 N. Calculate the number of beats heard per second when the wires are plucked.

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Detailed Solution

Fundamental frequency  f=12LTμ dfdT=12L12Tμ−1/21μ    ​⇒dfdT=14LTTμ+1/2=f2T     ⇒△f=f2⋅ΔTT=2002⋅1100= 1 cycle/sec.
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