Q.

Two identical wires are stretched by the same tension of 100 N, and each emits a note of frequency 200 cycles/sec. The tension in one wire is increased by 1 N. Calculate the number of beats heard per second when the wires are plucked.

Moderate

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By Expert Faculty of Sri Chaitanya

answer is 1.

(Detailed Solution Below)

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Detailed Solution

Fundamental frequency f=12LTμ dfdT=12L12Tμ−1/21μ ⇒dfdT=14LTTμ+1/2=f2T ⇒△f=f2⋅ΔTT=2002⋅1100= 1 cycle/sec.

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