Two infinite planes each with uniform surface charge density +σ are kept in such a way that the angle between them is 300. The electric field in the region shown between them is given by
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a
σ2ε01−32y^−x^2
b
σ2ε01+3y^+x^2
c
σε01+32y^+x^2
d
σ2ε01+3y^−x^2
answer is A.
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Detailed Solution
E→ = E→due to Upper plate + E→due to Lower plate⇒E→ =σ2ε0cos60º−x^+σ2ε0sin60º−y^ + σ2ε0y^⇒E→=σ2ε0cos60º−x^+σ2ε0−σ2ε0sin60ºy^ =σ2ε01−32y^−x^2