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Two infinite sheets having charge densities σ1 and σ2 are placed in two perpendicular planes whose two dimensional view is shown in the figure. The charges are distributed uniformly on sheets in electrostatic equilibrium condition. Four points are marked I, II, Ill and IV. The electric field intensities at these points are E→1,E¯2,E→3 and E¯4 respectively. The correct expression for electric field intensities is

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a

E→1=E→2=σ12+σ222ε0≠E→4

b

E→2=E→4=σ12+σ222ε0

c

E→1=E→2=E→3=E→4=σ12+σ222ε0

d

None of the above

answer is C.

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Detailed Solution

E→ due to infinite plane sheet having surface charge density a on its one face is σ2ε0 So E¯1=σ12ε0i^+σ22ε0j^ E¯2=-σ12ε0i^+σ22ε0j^ E→3=-σ12ε0i^-σ22ε0j^ E→4=σ12ε0i^-σ22ε0j^

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Two infinite sheets having charge densities σ1 and σ2 are placed in two perpendicular planes whose two dimensional view is shown in the figure. The charges are distributed uniformly on sheets in electrostatic equilibrium condition. Four points are marked I, II, Ill and IV. The electric field intensities at these points are E→1,E¯2,E→3 and E¯4 respectively. The correct expression for electric field intensities is