Two infinitely current carrying insulated wires AB and CD are carrying same current I. The wires cross each other at right angles as shown in figure. Three identical conductors $$P1Q1$$ , $$P2Q2$$ and $$P3Q3$$, carrying same current are placed a shown in figure and the forces acting on them are $$F1$$ , $$F2$$ and $$F3$$ respectively. Then select the correct option.

Question

Two infinitely current carrying insulated wires AB and CD are carrying same current  I. The wires cross each other at right angles as shown in figure. Three identical conductors $$P1Q1$$ , $$P2Q2$$ and $$P3Q3$$, carrying same current are placed a shown in figure and the forces acting on them are $$F1$$ , $$F2$$ and $$F3$$ respectively. Then select the correct option.

Infinity Learn · Accepted Answer

Magnetic induction at any point on the conductor P, Q $$=$$μ$$oI2$$$$π$$r−μ$$oI2$$$$π$$$$r=0$$.There fore $$F1$$ $$=$$ $$0$$.Magnetic induction at any point on the conductor $$P2Q2$$ is given by $$B2=$$μ$$oI2$$$$π$$$$r+$$μ$$oI2$$$$π$$$$r=$$μoI$$π$$r and its direction is outward. Now $$F2$$→$$=iP2Q2$$→ × $$B2$$→.Hence the direction of $$F2$$→ shown in the figure is right. Again magnetic induction at any point on the conductor $$P3Q3$$ is $$B3=$$μ$$oI2$$$$π$$$$r+$$μ$$oI2$$$$π$$$$r=$$μoI$$π$$r and its direction is inward. Since $$F3$$→$$=iP3Q3$$→ × $$B3$$→ , direction of $$F3$$→ shown in the diagram is wrong.

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