Two infinitely long straight current carrying wires are placed parallel to y-axis in xy plane. Each wire carries current I in opposite directions as shown. A charged particle of charge +q and mass m is projected from position P (0, 0, a) with initial velocity v→=vj→ .Then

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The magnitude of initial acceleration of the particle is μ0Iqv2πam

The direction of initial acceleration of the particle is parallel to positive x-axis

The direction of initial acceleration of the particle is parallel to positive y-axis

The radius of curvature of the path of the particle just after it is projected is 2πamvμ0Iq

answer is A.

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Detailed Solution

B→net=2Bcosθk^=2μ0I2π2a12k^=μ0I2πak^F→=q(vj^)×μ0I2πak^=μ0Iqv2πai^a→=F→m=μ0Iqv2πami^ Radius of curvature R=v2a=2πamv2μ0Iqv=2πamvμ0Iq

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