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Magnetic field due to current element

Question

Two infinitely long wires are placed perpendicular to the plane of paper. Current in wire A to 4i0 outward the plane of paper and current in ‘B’ is i0 inward the plane of paper. The α+αBdl along the QP is K(μ0i0). Find the value of K.

Difficult
Solution

Imagine a rectangular Amperian loop (cdefc) of very long length and very small breadth (almost zero).

For fc : Bdl=x sayFor cd : Bdl=0 Magnetic field is zero for large distancesFor de : Bdl=x symmetryFor ef : Bdl=0 Magnetic field is zero for large distancesFor loop cdefc, using Ampere's Law,Bdl=μ0ienclosedx+0+x+0=μ04i0x=μ02i0fcBdl=2μ0i0

Now, Imagine another rectangular Amperian loop (rstur) of very long length and very small breadth (almost zero).

For rs : Bdl=x sayFor st : Bdl=0 Magnetic field is zero for large distancesFor tu : Bdl=x symmetryFor ur : Bdl=0 Magnetic field is zero for large distancesFor loop rstur, using Ampere's Law,Bdl=μ0ienclosedx+0+x+0=μ0i0x=μ00.5i0rsBdl=0.5μ0i0 

Since, fcBdl and rsBdl are in same direction, we can add themα+αBdl=fcBdl+rsBdl =2μ0i0+0.5μ0i0=2.5μ0i0



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Figure shows an Amperian path ABCDA. Part ABC is in vertical plane PSTU while part CDA is in horizontal plane POQRS. Direction of circulation along the path is shown by an arrow near point B and at D.

B·d for this path according to Ampere’s law will be


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