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Q.

Two insects P and Q are firmly sitting at the ends of a massless semicircular wire of radius R and two more insects A and B are firmly sitting at the bottom of the wire. The wire is given an angular velocity ω0 about a vertical axis through its centre as shown in the figure. Mass of each insect is M. Now A and B crawl to the opposite ends to meet P and Q. Final angular velocity attained by the rod is equal to

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a

ω04

b

ω02

c

ω0

d

2ω0

answer is B.

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Detailed Solution

L→i=L→f2mR2ω0=2mR2+2mR2ω′               ω′=ω02
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