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Two insulating plates are both uniformly charged in such a way that potential difference between them is (V2 -V1 = 20 V) (i.e., plate 2 is at higher potential). The plates are separated by d = 0.1 m and can be treated as infintely large. An electron is released from rest on the inner surface of plate 1. What is its speed when it hits plate 2 ? (e = 1.6 x 10-19 C, me = 9.11x 10-31 kg)

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a

2⋅65×106m/s

b

7.02×1012m/s

c

1.87×106m/s

d

32×10−19m/s

answer is A.

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Detailed Solution

Given that V2 >V1 i.e., the electric field will point, from plate 2 to plate 1 as shown in fig. The moving electron will experience au electric force, opposite to the direction of electric field.Using work energy theorem, we havemev22−0=eV2−V1or 9⋅11×10−312v2=1⋅6×10−19×20∴ V=1.6×10−19×409.11×10−31 or V=2.65×106m/s.

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Two insulating plates are both uniformly charged in such a way that potential difference between them is (V2 -V1 = 20 V) (i.e., plate 2 is at higher potential). The plates are separated by d = 0.1 m and can be treated as infintely large. An electron is released from rest on the inner surface of plate 1. What is its speed when it hits plate 2 ? (e = 1.6 x 10-19 C, me = 9.11x 10-31 kg)