Two large tanks A and B, open at the top, contain different liquids. A small hole is made in the side of each tank at the same depth h below the liquid surface, but the hole in A has twice the area of the hole in B. The ratio of flow rates (volume flux) from the holes in A and B is
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a
2
b
0.5
c
4
d
0.25
answer is A.
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Detailed Solution
(Volume flux)A=vAAA=vB(2AB) (Volume flux)B=vBAB ⇒ Ratio = 2 : 1