Two liquids at temperature $$60$$° C and $$20$$° C respectively have masses in the ratio $$3$$:$$4$$ and the specific heats in the ratio $$4$$:$$5$$, if they are mixed the resultant temperature is:

Question

Infinity Learn · Accepted Answer

From Principle of method of mixtures,heat lost by hot liquid $$=$$ heat gained by cold liquid.given masses in the $$ratio=3$$:$$4specific$$ heats in the $$ratio=4$$:$$5let$$ hot liquid mass $$=3m$$, specific heat $$=4cnow$$ cold liquid $$mass=4m$$, specific heat $$=5cheat$$ lost by hot liquid $$=$$ m C∆$$T=3m(4c)(60-$$θ$$)heat$$ gain by cold liquid $$=m$$ C∆$$T=4m(5c)($$θ$$-20)$$   heat lost by hot liquid $$=heat$$ gain by cold liquid $$3m(4c)(60-$$θ$$)=4m(5c)($$θ$$-20)$$ ⇒θ$$=350C$$

Two liquids at temperature 60° C and 20° C respectively have masses in the ratio 3:4 and the specific heats in the ratio 4:5, if they are mixed the resultant temperature is:

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