Two liter glass flask contains some mercury. It is found that at all temperatures the volume of the air inside the flask remains same. The volume of the mercury in side the flask isα for  glass=9×10−6/0C,  γHg=1.8×10−4/0Cx×10−6m3 where x=

at all temperatures the volume of the air inside the flask remains same VCγC=VLγL ; here V is volume of container and volume of liquid; γ coefficient of volume expansion of container and liquid  VL=VCγCγL given VC=2liter;γC=3α=3x9x10-6/C  0;γL=1.8x10-4/C  0, substitute VL=2literx3x9x10-61.8x10-4        since 1liter=10-3m3 VL=300x10-6m3=volume of mercury in the flask