First slide

Magnetism

Question

Two long bar magnets are placed with their axes coinciding in such away that the north pole of the first magnet is 1.0 cm from the south pole of the second. If both the magnets have a pole strength of 40 Am. The force exerted by one magnet on the other is__N

Moderate

Solution

As the magnets are described as long, only interaction between the nearest poles is considered
Given : $m_{1} = m_{2} = 40 A m; r = 1 c m = 1 \times 10^{- 2} m$
Force exerted by two magnetic poles on each other $= \frac{μ_{0}}{4 π} . \frac{m_{1} m_{2}}{r^{2}}$
$= \frac{10^{- 7} \times 40 \times 40}{{(1 \times 10^{- 2})}^{2}} = \frac{10^{- 7} \times 16 \times 10^{2}}{1 \times 10^{- 4}} = \frac{16 \times 10^{2} \times 10^{- 3}}{1} = 16 \times 10^{- 1} = 1.6 N$

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