Q.

Two long conductors 10 cm apart carry currents in the ratio 1 :2 in the same direction. The magnetic field midway between them is 2 ×  10−3 T The force on unit length of any one conductor will be

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a

2π × 10−3 N

b

2 × 10−3 N

c

π  N

d

1 N

answer is D.

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Detailed Solution

Magnetic field at their mid-point,B=μ02πd2  2i−i  = μ0iπdGiven  μ0iπd  =  2 ×  10−3 TSubstituting d = 0.1 m, we get i=1032 AMagnetic field at the location of second conductor due to first conductor is, B=μ0i2πdForce on unit length of second conductor=B×  2i=μ0i2πd =  μ0iπd × i =  1N
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