Q.
Two long conductors 10 cm apart carry currents in the ratio 1 :2 in the same direction. The magnetic field midway between them is 2 × 10−3 T The force on unit length of any one conductor will be
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a
2π × 10−3 N
b
2 × 10−3 N
c
π N
d
1 N
answer is D.
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Detailed Solution
Magnetic field at their mid-point,B=μ02πd2 2i−i = μ0iπdGiven μ0iπd = 2 × 10−3 TSubstituting d = 0.1 m, we get i=1032 AMagnetic field at the location of second conductor due to first conductor is, B=μ0i2πdForce on unit length of second conductor=B× 2i=μ0i2πd = μ0iπd × i = 1N
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