Questions
Two long conductors, separated by a distance d, carry current I1 and I2 in the same direction. They exert a force F on each other. Now, the current in one of them is increased to two times and its directions is reversed. The distance is also increased to 3d. The new value of the force between them is
detailed solution
Correct option is C
F ∝ i1 i2a ; Since one of the current increases two times and distance increases three times, so force become 23 times. Also due to the reversal of direction of current, force becomes repulsive and hence negative.Talk to our academic expert!
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