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Q.

Two long conductors, separated by a distance d carry current I1 and I2 in the same direction. They exert a force F on each other. Now the current in one of them is increased to two times and direction is reversed. The distance is also increased to 3d. The value of the force between them is

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a

-2F

b

F/3

c

-2F/3

d

–F/3

answer is C.

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Detailed Solution

Case(i) F=μ0I1I22πd (attractive) Case(ii) F1=μ0(2I1)I22π(3d) (repulsive) ⇒F1=−23F (negative →repulsive)

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