Two long and parallel wires are at a distance of 0.1 m and a current of 5 A is flowing in each of these wires. The force per unit length due to these wires will be

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5 × 10−5 N/m

5 × 10−3 N/m

2.5 × 10−5 N/m

2.5 × 10−4 N/m

answer is A.

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Detailed Solution

F=μ04π 2×i1i2a = 10−7 × 2 × 5 × 50.1= 5 × 10−5N/m

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