Two long parallel wires separated by a distance d have equal current i flowing in each. The magnetic field of one exerts a force F on the other. The distance d is increased to $$2$$ d and current in each wire is reduced from i to i $$/$$ $$2$$ What is the force between them now ?

Question

Infinity Learn · Accepted Answer

Force per unit length of the wire is given $$byF=$$μ$$04$$π×$$2i1i2d=$$μ$$04$$π×$$2i2d$$ ∵$$i1=i2=iWhen$$ d is increased to $$2$$ d and i is reduced to i $$/$$ $$2$$, thenF′$$=m04$$π×$$2(i/2)22d=$$μ$$04$$π×$$2i28d=18$$μ$$04$$π×$$2i2d=F/8$$

Two long parallel wires separated by a distance d have equal current i flowing in each. The magnetic field of one exerts a force F on the other. The distance d is increased to 2 d and current in each wire is reduced from i to i / 2 What is the force between them now ?

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