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Q.

Two long parallel wires separated by a distance d have equal current i flowing in each. The magnetic field of one exerts a force F on the other. The distance d is increased to 2 d and current in each wire is reduced from i to i / 2 What is the force between them now ?

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a

F

b

F/2

c

F/4

d

F/8

answer is D.

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Detailed Solution

Force per unit length of the wire is given byF=μ04π×2i1i2d=μ04π×2i2d ∵i1=i2=iWhen d is increased to 2 d and i is reduced to i / 2, thenF′=m04π×2(i/2)22d=μ04π×2i28d=18μ04π×2i2d=F/8
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