Two loud speakers are being compared, and one is perceived to be 32 times louder than the other. What will be the difference in intensity levels between the two when measured in decibels?

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answer is 15.

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Detailed Solution

in general change in the intensity level form of I1 to I2, ΔL=10log10⁡I2I1dB here I2=32I1 so ∆L=10 log 32=10 log 25=50 log2=50×0.3010=15

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