Two magnets of equal mass are joined at right angles to each other as shown. The magnet 1 has a magnetic moment 3 times that of magnet 2. This arrangement is pivoted so that it is free to rotate in the horizontal plane. In equilibrium, what angle will the magnet 1 subtend with the magnetic meridian?
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a
tan-112
b
tan-113
c
tan-11
d
0o
answer is B.
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Detailed Solution
For equilibrium of the system torques on M1 and M2 due to BH must counter balance each other i.e., M1 x BH=M2 x BH. lf θ is the angle between M1 and BH then the angle between M2 and BH will be 90o-θ; So M1BH sinθ=M2BH sin 90o-θ⇒tan θ=M2M1=M3M=13⇒θ=tan-113