Two magnets of magnetic moments M and 3M are joined to form a cross +. The combination is suspended freely in a uniform magnetic field. In the equilibrium position, the angle between the magnetic moment 3M and the field is

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30o

45o

60o

90o

answer is A.

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Detailed Solution

3MBsinθ=MBsin(90-θ)⇒tanθ=13⇒θ=30°

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