Questions
Two masses are connected by a string which passes over a pulley accelerating upward at a rate A shown. If be the accelerations of bodies I and 2 respectively then,
detailed solution
Correct option is C
Since length of the string is constant. So,(YP-y1) + πR + (Yp-y2) = constant. So,Take second derivative of both sides twice w.r.t. time t, We get ,(A-a1)+0+[A--a2]=0 ⇒A=a1-a22Talk to our academic expert!
Similar Questions
Two masses of I kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in figure. The masses start moving during this interval; the reading of spring balance will be:
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