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Questions  

Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown in fig. The coefficient of friction of A 

with the table is 0.2 The minimum mass of C that may be placed on A to prevent it from moving is equal to

a
15 kg
b
10 kg
c
5 kg
d
0 kg

detailed solution

Correct option is A

Let T = tension in the string, f = frictional force between block A and table, x = minimum mass of C. For the system to be in equilibriumf = T (for block A) ...(1)where f=μmg=μ(10+x)g=0⋅2(10+x)g∴T=0⋅2(10+x)g      ...(2)For the equilibrium of B,t = 5g   …(3)From eqs. (2) and (3), we get0⋅2(10+x)g=5g or 2+0⋅2x=5 or 0⋅2x=3 or  X=30⋅2=15kg.

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