Questions
Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown in fig. The coefficient of friction of A
with the table is 0.2 The minimum mass of C that may be placed on A to prevent it from moving is equal to
detailed solution
Correct option is A
Let T = tension in the string, f = frictional force between block A and table, x = minimum mass of C. For the system to be in equilibriumf = T (for block A) ...(1)where f=μmg=μ(10+x)g=0⋅2(10+x)g∴T=0⋅2(10+x)g ...(2)For the equilibrium of B,t = 5g …(3)From eqs. (2) and (3), we get0⋅2(10+x)g=5g or 2+0⋅2x=5 or 0⋅2x=3 or X=30⋅2=15kg.Talk to our academic expert!
Similar Questions
A skier starts from rest at point A and slides down the hill without turning or breaking. The friction coefficient is . When he stops at point B, his horizontal displacement is s. What is the height difference between points A and B?
(The velocity of the skier is small, so that the additional pressure on the snow due to the curvature
can be neglected. Neglect also the friction of air and the dependence of on the velocity of the skier.)
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