First slide

Moment of intertia

Question

Two masses each of mass M are attached to the end of a rigid massless rod of length L. The moment of inertia of the system about an axis passing centre of mass and perpendicular to its length is

Moderate

A

$\frac{{ML}^{2}}{4}$
B

$\frac{{ML}^{2}}{2}$
C

${ML}^{2}$
D

2 ${ML}^{2}$

Solution

The moment of inertia of the system about the given axis is
$I = M {(\frac{L}{2})}^{2} + M {(\frac{L}{2})}^{2} = \frac{{ML}^{2}}{4} + \frac{{ML}^{2}}{4} = \frac{{ML}^{2}}{2}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App