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Question

Two masses 5 kg and 3 kg are suspended from the ends of an unstretchable light string passing over a frictionless pulley. When the masses are released, the thrust on the pulley is (g = 10ms^–2)

Moderate

Solution

$\large T = \left( {\frac{{2{m_1}{m_2}g}}{{{m_1} + {m_2}}}} \right) = \frac{{2 \times 5 \times 3 \times 10}}{8} = 37.5N$
Where T = tension induced in the string.
$\large \therefore$ Thrust on pulley = 2T ⇒ 2(37.5) ⇒ 75N.

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