First slide

Second law

Question

Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. At the instant when the 10 kg mass has an acceleration of the acceleration of $12 {ms}^{- 2},$ the 20 kg mass is

Easy

A

$2 {ms}^{- 2}$
B

$4 {ms}^{- 2}$
C

$10 {ms}^{- 2}$
D

$20 {ms}^{- 2}$

Solution

$\begin{array}{l} F = m_{1} a_{1} + m_{2} a_{2} \\ 200 = 10 \times 12 + 20 \times a_{2} \Rightarrow a_{2} = 4 {ms}^{- 2} \end{array}$

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