Questions
Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. At the instant when the 10 kg mass has an acceleration of the acceleration of the 20 kg mass is
detailed solution
Correct option is B
F=m1a1+m2a2200=10×12+20×a2⇒a2=4ms−2Talk to our academic expert!
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Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.
Statement II : The equality of mg and R has no connection with the third law.
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