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Q.

Two masses 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. At the instant shown in figure, the 10 kg mass has acceleration of 12 m/s2. The value of acceleration of 20 kg mass is

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a

4 m/s2

b

10 m/s2

c

20 m/s2

d

30 m/s2

answer is A.

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Detailed Solution

Given, m1=10 kg,m2=20 kg,F2=200 N,a1=12 m/s2,  a2 = ?For mass m1,F1 = m1a1 = 10 x 12 = 120 NFor mass m2,F2 - F1 = m2a2200 - 120 = 20 × a2⇒  a2 = 8020 = 4 ms-2
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