Newton's laws of motion

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Question

Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass at the instant when the 10 kg mass has an acceleration of 12 ms^-2 towards right, find the acceleration of the 20kg mass in ms^-2.

Moderate

Solution

$Force on 10 kg block K x = m a = 12 \times 10 = 120 N$
So
$a = \frac{80}{20} = 4 m / s^{2}$

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