Two masses $$m1$$ $$=1$$ kg and $$m2=$$ $$2$$ kg and connected by a light inextensible string and suspended by means of a weightless pulley as shown in the figure. Assuming that both the masses start from rest, the distance travelled by the centre of mass in two seconds is (Take$$ g $$=$$ $$10$$ $$ms-2)

Question

Two masses $$m1$$ $$=1$$ kg and $$m2=$$ $$2$$ kg and connected by a light inextensible string and suspended by means of a weightless pulley as shown in the figure. Assuming that both the masses start from rest, the distance travelled by the centre of mass in two seconds is (Take$$ g $$=$$ $$10$$ $$ms-2)

Infinity Learn · Accepted Answer

Here $$m1$$ $$=$$ $$1$$ kg, $$m2$$ $$=$$ $$2$$ kgThe acceleration of the system is a $$=$$ (m2-m1)gm1+m2$$ $$=$$ $$(2-1)g(1+2)  $$=$$ $$g3$$ $$=$$ $$103Acceleration$$ of the centre of mass isacm  $$=$$ $$m1a1+m2a2m1+m2$$ $$=$$ $$1(-a)+2(a)1+2$$          $$=$$ $$(-g3)+2(g3)3$$ $$=$$ $$g9$$ $$=$$ $$109$$ $$ms-2The$$ distance travelled by the centre of mass in two seconds isS $$=$$ $$12acmt2$$ $$=$$ $$12$$×$$109$$×$$(2)2$$ $$=$$ $$209m$$

Two masses $m_{1} =$ 1 kg and $m_{2}$ = 2 kg and connected by a light inextensible string and suspended by means of a weightless pulley as shown in the figure. Assuming that both the masses start from rest, the distance travelled by the centre of mass in two seconds is (Take g = 10 ${ms}^{- 2}$ )

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Two masses m1 =1 kg and m2= 2 kg and connected by a light inextensible string and suspended by means of a weightless pulley as shown in the figure. Assuming that both the masses start from rest, the distance travelled by the centre of mass in two seconds is (Take g = 10 ms-2)

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Two masses $m_{1} =$ 1 kg and $m_{2}$ = 2 kg and connected by a light inextensible string and suspended by means of a weightless pulley as shown in the figure. Assuming that both the masses start from rest, the distance travelled by the centre of mass in two seconds is (Take g = 10 ${ms}^{- 2}$ )