Questions
Two masses m and 2m are attached to two ends of an ideal spring as' shown in figure. When the spring is
in the compressed state, the energy of the spring is 60J, if the spring is released, then at it:- natural length, [BHU 2012]
detailed solution
Correct option is B
According to law of conservation of momentum,mv1+2mv2=0 or v2=-v12 …(i)According to law of conservation of energy,12mv12+122mv22=60⇒ 12mv12+m-v122=60⇒ 12mv12+14mv12=60⇒ 3mv124=60⇒ 12mv12=40 JTalk to our academic expert!
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