Two masses m and 2m are attached to two ends of an ideal spring and the spring is in the compressed state. The energy of spring is 60 joule. If the spring is released, then
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
the energy of both bodies will be same
b
energy of smaller body will be 10J
c
energy of smaller body will be 20J
d
energy of smaller body will be 40 J
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Fext =0 From momentum conservation P1+P2=0 m1v1+(-m2v2)=0 m1m2=v2v1&v2v1=12 k1k2=m1v12m2v22=12212=2 Now k1+k2=60 ⇒k1+k12=60 =k1=40 J
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
Two masses m and 2m are attached to two ends of an ideal spring and the spring is in the compressed state. The energy of spring is 60 joule. If the spring is released, then