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Two masses m and M are attached with strings as shown. For the system to be in equilibrium we have
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Correct option is
mg = 2Tsin 450 mg = 2TT1cos θ = T cos 450T1cosθ = T2 =mg2{∵ T = mg2}Further, Mg + T cos 450 = T1 sin θT1 sin θ = Mg + mg212T1sin θ = Mg+mg2tan θ = Mg+mg2mg2 = 1+2MmTalk to our academic expert!
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Two masses of I kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in figure. The masses start moving during this interval; the reading of spring balance will be:
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