Q.

Two masses m and M are attached with strings as shown. For the system to be in equilibrium we have

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a

tan θ = 1+ 2Mm

b

tan θ = 1+ 2mM

c

tan θ = 1+M2m

d

tan θ = 1+m2M

answer is .

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Detailed Solution

mg = 2Tsin 450       mg = 2TT1cos θ = T cos 450T1cosθ = T2 =mg2{∵ T = mg2}Further, Mg + T cos 450 = T1 sin θT1 sin θ = Mg + mg212T1sin θ = Mg+mg2tan θ = Mg+mg2mg2 = 1+2Mm
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Two masses m and M are attached with strings as shown. For the system to be in equilibrium we have