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An Intiative by Sri Chaitanya
a
m1gsinθ1+m2gsinθ2m1+m2
b
m1gsinθ1-m2gsinθ2m1-m2
c
m1gsinθ1-m2gsinθ2m1+m2
d
m1+m2sinθ1+sinθ2gm1-m2
answer is C.
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