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Q.

Two masses m1 and m2(m2 > m1) are positioned as shown in figure, m1 being on the ground and m2 at a height h above the ground. When m2 is released, the speed at which it hits the ground will be

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a

2ghm1m2

b

2ghm1−m2m1+m2

c

2ghm1+m2m1−m2

d

2ghm2−m1m1+m2

answer is D.

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Detailed Solution

Since, a=m2−m1m2+m1g and v2−u2=2a s              ⇒v2−02=2m2−m1m2+m1gh⇒v=2m2−m1m2+m1gh
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