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Q.

Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass 1.96×10−15kg is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is

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a

15e

b

3e

c

6e

d

8e

answer is B.

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Detailed Solution

For equilibrium mg = qE∴1.96×10−15×9.8=q×8000.02⇒q=1.96×10−15×9.8×0.02800⇒n×1.6×10−19=1.96×10−15×9.8×0.02800⇒n=3
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