Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally; A particle of mass 1.96 × 10−15kg is suspended in equilibrium between the plates. If e is the elementary

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8 e

6 e

3 e

answer is C.

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Detailed Solution

In equilibrium, F=mg q E=mg (n e) Vd=mg n=mg de V=1.96 × 10−15×9.8×0.021.6 × 10−19× 800=3Therefore, q=3 e .

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