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Two metal spheres, one of radius R and the other of radius 2R , both have same surface charge density σ . They are brought in contact and separated. What will be new surface charge density on larger sphere

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a

σ/6

b

3σ/4

c

5σ/6

d

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answer is C.

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Detailed Solution

Qi=Qfσ(4πR2)+σ4π(4R2)=(σ1)4πR2+σ24π(4R2) E=VR=σ∈0  and σ α1Rσ1σ2=2⇒σ2=5σ6
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