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Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?

a
σ1=56σ, σ2=52σ
b
σ1=52σ, σ2=56σ
c
σ1=52σ, σ2=53σ
d
σ1=53σ, σ2=56σ

detailed solution

Correct option is D

when spheres are kept in contact, charge redistribution takes place to get same potential. Total combined charge = 20πR2σ. Potential of both the spheres become equal, hence Q = QI2 where Q is the charge on sphere of radius R and QI is the charge on sphere of radius 2R.Thus charge on sphere of radius R becomes 20πR2σ3 , while charge on sphere of radius 2R becomes 40πR2σ3Hence new charge densities will beσ1=53σ, σ2=56σ

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Similar Questions

Two spherical shells are as shown in figure.

Let r be the distance of a point from their common centre.  Then, match the following columns and mark the correct choice from the given codes.

 Column-I Column-II
i.Electric field for r < R1p.is constant for q2 and vary for q1
ii.Electric potential for r < R1q.is zero for q2 and vary for q1
iii.Electric potential for R1 < r <R2r.is constant
iv.Electric field for R1 < r <R2s.is zero

Codes:


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