Q.
Two metal wires of identical dimensions are connected in series. If σ1 and σ2 are the conductivities of the metal wires respectively, the effective conductivity of the combination is
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a
σ1+σ2σ1σ2
b
σ1σ2σ1+σ2
c
2σ1σ2σ1+σ2
d
σ1+σ22σ1σ2
answer is C.
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Detailed Solution
As both metal wires are of identical dimensions, so their length and area of cross-section will be same. Let them be I and A respectively. Then The resistance of the first wire isR1=lσ1A ....(i)and that of the second wire is R2=lσ2A ...(ii)As they are connected in series, so their effective resistance isRs=R1+R2=lσ1A+lσ2A ( using (i) and (ii))=lA1σ1+1σ2 . . .(iii)If σeff is the effective conductivity of the combination, thenRs=2lσeff A . . . .(iv)Equating eqns. (iii) and (iv), we get 2lσeffA=lA1σ1+1σ22σeff =σ2+σ1σ1σ2⇒σeff =2σ1σ2σ1+σ2
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