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Q.

Two metallic wires made of different material, having resistivity ρ and 2ρ are connected in series combination as shown in the figure. The wires have same cross sectional area. When an electric current passes through the composite wire, intensities of electric fields in wire 1 and 2 are E1 and E2 respectively.

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a

E1E2=12

b

E1E2=2

c

E1E2=19

d

E1E2=1

answer is A.

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Detailed Solution

EJ=resistivity for same cross sectional area, current density (J) is same in both wires.∴E∝resistivity     and    E1E2=ρ2ρ=12.
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