Two metallic wires made of different material, having resistivity ρ and 2ρ are connected in series combination as shown in the figure. The wires have same cross sectional area. When an electric current passes through the composite wire, intensities of electric fields in wire 1 and 2 are E1 and E2 respectively.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
E1E2=12
b
E1E2=2
c
E1E2=19
d
E1E2=1
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
EJ=resistivity for same cross sectional area, current density (J) is same in both wires.∴E∝resistivity and E1E2=ρ2ρ=12.
Two metallic wires made of different material, having resistivity ρ and 2ρ are connected in series combination as shown in the figure. The wires have same cross sectional area. When an electric current passes through the composite wire, intensities of electric fields in wire 1 and 2 are E1 and E2 respectively.