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Two metals are mixed together in equal volumes to form an alloy of specific gravity 4. When equal masses of the same two metals are mixed together, the specific gravity of metal is 3, the specific gravity of each metal is

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a

4 and 6

b

2 and 6

c

2 and 4

d

4 and 8

answer is B.

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Detailed Solution

Case 1: ρ=ρ1+ρ22 4=ρ1+ρ22 ρ1+ρ2=8--(1) Case 2: ρ=2ρ1ρ2ρ1+ρ2 3=2ρ1ρ28 ρ1ρ2=12---(2) from (1) & (2) ρ1-ρ22=ρ1+ρ22-4ρ1ρ2 =82-4(12)=64-48=16 ρ1-ρ2=4---(3) from (1) &(3) ρ1+ρ2=8--(1) ρ1-ρ2=4---(3) we get ρ1=6g/cc Therefore ρ2=2g/cc

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