Two metals are mixed together in equal volumes to form an alloy of specific gravity 3. When equal masses of the same two metals are mixed together, the specific gravity of metal is 83 . The specific gravity of each metal is

Equal volumes ρ=ρ1+ρ22⇒ρ1+ρ2⇒2×3=6----(1) Equal masses ρ=2ρ1ρ2ρ1+ρ2⇒83=2ρ1ρ26                ρ1ρ2=243=8 ρ1-ρ22=ρ1+ρ22-4ρ1ρ2 ρ1-ρ22=62-48=4 ρ1-ρ2=2 from (1)  ρ1+ρ2=6 ρ1-ρ2=2 _________ 2ρ1=8 ________                ⇒ρ1=4,  ρ2=2