Two moles of an ideal monoatomic gas is expanded according to the process AB as shown in the figure. Then heat supplied to the gas is
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a
2p0v0
b
3p0v0
c
4p0v0
d
6p0v0
answer is D.
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Detailed Solution
The process AB is given by, P=p0v0VAlso, PV = nRT∴T=PVnR=p0V2nRv0. At V=2v0, TB=p0(2v0)2nRv0=4p0v0nR, and V=v0, TA=p0v0nR∴∆U=n.3R2(TB-TA)=n.3R24p0v0nR-p0v0nR=92p0v0W = Area under P-V graph =12(2p0+p0)(2v0-v0)=32p0v0∴Heat supplied =∆U+W=6p0v0