Two moles of an ideal monoatomic gas occupies a volume V at 270C. The gas expands adiabatically to a volume 2V. Calculate final temperature
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a
195K
b
190K
c
196K
d
189K
answer is D.
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Detailed Solution
adiabatic relation between temperature T, volume V is TVγ-1=constantT1V1γ-1=T2V2γ-1⇒T2=T1V1V2γ-1 for monoatomic gas, γ=53 ⇒T2=(27+273kelvin)V2V53-1⇒T2=189K