Two monkeys $$M1$$ and $$M2$$ of equal mass 'm' can climb strings of a pulley arrangement as shown in figure. Find magnitude of acceleration (in$$ $$m/s2) of $$M1$$ with respect to rope so that block remains stationary. It is given that $$M2$$ is just holding the string. Assume pulley is frictionless and string is massless and inextensible.

Question

Infinity Learn · Accepted Answer

$$T=5mga2=5mg$$−$$mgm=4gT$$′$$=2T=10mga1=10mg$$−$$mgm=9gAcceleration$$ of the rope is equal to the acceleration of the moving pulley. Hence acceleration of $$M1$$ with respect to $$ropeaM1$$, Rope $$=9g$$−$$($$−$$2g)=11g=110m/s2$$

Application of Newtons laws

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Application of Newtons laws

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T=5mga2=5mg−mgm=4gT′=2T=10mga1=10mg−mgm=9gAcceleration of the rope is equal to the acceleration of the moving pulley. Hence acceleration of M1 with respect to ropeaM1, Rope =9g−(−2g)=11g=110m/s2

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